Calculating Column Sums and Differences Between Rows in a Grouped Table
In this article, we’ll delve into the world of SQL query optimization and explore how to calculate column sums and differences between rows in a grouped table.
Understanding the Problem Statement
The problem statement presents two tables: table1 and table2. The goal is to calculate the difference between rows based on group by SELL_ID in table1, which will produce the desired output in table2.
Here’s an excerpt from table1:
+---------+---------+----------+----------+------------------+---------+
| seq_ID | REQ_ID | CALL_ID | SELL_ID | REGION | COUNT |
+---------+---------+----------+----------+------------------+---------+
| 1 | 123 | C001 | S1 | AGL | 510563 |
| 2 | 123 | C001 | S1 | USL | 122967 |
| 3 | 123 | C001 | S1 | VALIC | 614106 |
| 4 | 123 | C001 | S2 | Inforce |1247636 |
| 5 | 123 | C001 | S2 | NB | 0 |
| 6 | 123 | C001 | S3 | Seriatim Summary |1247636 |
+---------+---------+----------+----------+------------------+---------+
And here’s the desired output in table2:
+---------+---------+----------+----------+-------+
| seq_ID | REQ_ID | CALL_ID | Summary | COUNT |
+---------+---------+----------+----------+-------+
| 1 | 123 | C001 | S1_vs_S2 | 0 |
| 2 | 123 | C001 | S2_vs_S3 | 0 |
| 3 | 123 | C001 | S3_vs_s1 | 0 |
+---------+---------+----------+----------+-------+
The Initial Query
The initial query provided by the user is as follows:
INSERT INTO table2 (SEQ_ID, REQ_ID,call_id,summary,count)
SELECT min(seq_id) seq_id
, req_id
, call_id
, S1_vs_S2
,((SELECT sum(c2) FROM TABLE_STG_CTRL WHERE source='S1')-
SELECT sum(c2) FROM TABLE_STG_CTRL WHERE source='S2'))
FROM table1
GROUP BY req_ID, Ctrl_ID, c1, source
ORDER BY SEQ_ID ;
Issues with the Initial Query
There are several issues with this query:
- The
Ctrl_IDandsourcecolumns are not present intable1, which will cause a syntax error. - The
S1_vs_S2column is calculated using subqueries, which can be slow for large tables. - The query uses the
ORDER BY SEQ_IDclause, but this does not guarantee any specific order of rows.
Optimized Query
The optimized query to solve this problem is as follows:
SELECT req_id, call_id, sell_id,
lead(sell_id) over (partition by req_id, call_id order by seq_id) as next_sell_id,
(cnt -
lead(cnt) over (partition by req_id, call_id order by seq_id)
) as diff
from (select req_id, call_id, sell_id, sum(count) as cnt, min(seq_id) as seq_id
from t
group by req_id, call_id, sell_id
) t
How the Optimized Query Works
This query uses a combination of window functions and subqueries to achieve the desired output.
- The subquery calculates the sum of
countvalues for each group of rows with the samereq_id,call_id, andsell_id. - The outer query selects these sums as
cntcolumns. - The
leadwindow function is used to calculate the difference between consecutive rows for each group.
How Window Functions Work
Window functions in SQL allow you to perform calculations across a set of rows that are related to the current row, such as aggregating values or calculating differences between rows.
In this case, the lead window function calculates the next value in the sequence (next_sell_id) and the difference between consecutive rows (diff).
Advantages of the Optimized Query
This query has several advantages over the initial query:
- It is more efficient because it avoids using subqueries to calculate column sums.
- It is more accurate because it ensures that the results are ordered correctly.
Conclusion
Calculating column sums and differences between rows in a grouped table can be a challenging task. However, by understanding how window functions work and applying them correctly, you can achieve efficient and accurate results.
Last modified on 2025-05-05